an isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm find the area of the triangle
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24
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Anonymous:
wrong
Answered by
48
hey
Perimeter=l+b
30=12+12
30-24=6
Semiperimeter=a+b+c/2
12+12+6/2=15
area of triangle=[S (s×a)(s×b)(s×c)]
=15 (15×12)(15×12)(15×6)
=15×180×180×90
=3×5×2×2×3×3×5×2×2×3×3×5×2×3×3×5
=2700underroot 6
Perimeter=l+b
30=12+12
30-24=6
Semiperimeter=a+b+c/2
12+12+6/2=15
area of triangle=[S (s×a)(s×b)(s×c)]
=15 (15×12)(15×12)(15×6)
=15×180×180×90
=3×5×2×2×3×3×5×2×2×3×3×5×2×3×3×5
=2700underroot 6
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