Question

An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm . Find the are of the triangle​

Answer 1

Answer:

$9 \sqrt{} 15 \: cm {}^{2}$

Step by Step explaination:

Let the third side of isosceles triangle be x. Perimeter = 30 cm

Let the third side of isosceles triangle be x. Perimeter = 30 cm => x + 12 + 12 = 30

Let the third side of isosceles triangle be x. Perimeter = 30 cm => x + 12 + 12 = 30 => x + 24 = 30

Let the third side of isosceles triangle be x. Perimeter = 30 cm => x + 12 + 12 = 30 => x + 24 = 30 => x = 6 cm

Let the third side of isosceles triangle be x. Perimeter = 30 cm => x + 12 + 12 = 30 => x + 24 = 30 => x = 6 cm => 2s = 30 cm

Let the third side of isosceles triangle be x. Perimeter = 30 cm => x + 12 + 12 = 30 => x + 24 = 30 => x = 6 cm => 2s = 30 cm => s = 15 cm

Let the third side of isosceles triangle be x. Perimeter = 30 cm => x + 12 + 12 = 30 => x + 24 = 30 => x = 6 cm => 2s = 30 cm => s = 15 cmar.(triangle)=

$\sqrt{s(s - a)(s - b)(s - c}$

=

$\sqrt{15(15 - 12)(15 - 2)(15 - 6)}$

=

$\sqrt{15 \times 3 \times 3 \times 9}$

=

$9 \sqrt{15 \:} cm ^{2}$