Question

An isosceles triangle has perimeter 30 cm and each of the equal sides

is 12 cm. Find the area of the triangle.​

Answer 1

Answer:

Isosceles triangle

Solve for area

A ≈ 40.25cm²

(b) Base = 12cm

(P) Perimeter = 30cm

Step-by-step explanation:

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Answer 2

Answer:

Perimeter of isosceles triangle=30cm

Length of equal sides=12cm

Let third side of triangle=xcm

According to problem,

x+12+12=30

x+24=30

x=30−24

x=6

∴ Third side of triangle=6cm

Using Heron's formula

Area of triangle= √s(s−a)(s−b)(s−c) sq. units

where s=a+b+c/2

s=30/2

s=15

Area of triangle= √15(15−12)(15−12)(15−6)cm square .

=√15×3×3×9

=3×3× √ 15

=9√15cm square

area of triangle = 9 √15 cm square....

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