An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.
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Answered by
3
Answer:
Perimeter of isosceles triangle=30cm
Length of equal sides=12cm
Let third side of triangle=xcm
According to problem,
x+12+12=30
x+24=30
x=30−24
x=6
∴ Third side of triangle=6cm
Using Heron's formula
Area of triangle=
s(s−a)(s−b)(s−c)
sq. units
where s=
2
a+b+c
s=
2
30
=15
Area of triangle=
15(15−12)(15−12)(15−6)
cm
2
=
15×3×3×9
cm
2
=3×3×
15
cm
2
=9
15
cm
2
∴ Area of triangle=9
15
cm
2
.
Hope it's help you!!!
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4
Answer:
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