Question

an isosceles triangle has perimeter 30cm and each of the equal side is 12 centimetre find the area of the triangle​

Answer 1

Let the unequal side be x

Perimeter of Triangle is sum of it's sides.

Therefore,

12+12+x = 30

24 + x = 30

x = 30-24

x = 6

$area \: = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ s \: = \frac{30}{2} = 15 \\ \\ a = 12 \\ b = 12 \\ c = 6 \\ \\ \sqrt{15(15 - 12)(15 - 12)(15 - 6)} \\ \\ \sqrt{15 \times 3 \times 3 \times 9} \\ \\ \sqrt{1215} \\ \\ 9 \sqrt{15} \: {cm}^{2}$

Answer 2

Answer:hope it will help you

Explanation: