Question

An isosceles triangle has perimeter 40 cm and and its base is 20 CM find the length of the altitude to one of the equal side

Answer 1

Step-by-step explanation:

$x + x + 20 = 40$

$2x = 20$

$x = 10$

each equal sides of the triangle = 10

Length of altitude to one of the equal side

can be written as

$\sqrt{ {10}^{2} - {5}^{2} }$

$= \sqrt{100 - 25}$

$= 5 \sqrt{3}$

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