Question

An Isosceles triangle has perimeter 45cm and each of equal side be 16cm.

Find area of triangle and length of Altitudes in form of square root​

Answer 1

HEY MATE,

ANSWER:}

A≈96.75cm²

Answer 2

Answer:

Area is 12 times root 65

Step-by-step explanation:

let us assume the triangle to be labelled as ABC where AB = BC and AC is base which is = 16cm.

Now perimeter= 45cm

AB + BC + AC = 45

AB + AB + 16 = 45

2AB = 45-16

2AB = 29 cm

thus,

AB = BC = 29/2 = 14.5 cm

NOW USING HERRON'S FORMULA

firstly, s=p/2 =22.5 cm

AREA=

root{s(s-AB)(s-BC)(s-AC)}

root{22.5(22.5-14.5)(22.5-14.5)(22.5-16)}

root{22.5 × 8 × 8 × 6.5}

8 × root {225/10 × 65/10}

8/10 root {225 × 65}

0.8 × root {(15 × 15)(5 × 13)}

0.8 ×15 root {65}

12 × root 65 cm square