An Isosceles triangle has perimeter 45cm and each of equal side be 16cm.
Find area of triangle and length of Altitudes in form of square root
Answers
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1
HEY MATE,
ANSWER:}
A≈96.75cm²
Answered by
9
Answer:
Area is 12 times root 65
Step-by-step explanation:
let us assume the triangle to be labelled as ABC where AB = BC and AC is base which is = 16cm.
Now perimeter= 45cm
AB + BC + AC = 45
AB + AB + 16 = 45
2AB = 45-16
2AB = 29 cm
thus,
AB = BC = 29/2 = 14.5 cm
NOW USING HERRON'S FORMULA
firstly, s=p/2 =22.5 cm
AREA=
root{s(s-AB)(s-BC)(s-AC)}
root{22.5(22.5-14.5)(22.5-14.5)(22.5-16)}
root{22.5 × 8 × 8 × 6.5}
8 × root {225/10 × 65/10}
8/10 root {225 × 65}
0.8 × root {(15 × 15)(5 × 13)}
0.8 ×15 root {65}
12 × root 65 cm square
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