Math, asked by rizwishaan7p7nglp, 6 months ago

An isosceles triangle has perimeter 45cm and each of equal side
be 16cm. Find area of triangle and length of Altitudes in form of
square root

Answers

Answered by aquibkhanmaaq211
0

Answer:

in isosceles triangle both sides are equal.

Given that:

perimeter=45cm

equal side=15cm.

To find

area of triangle and lenght of altitude

perimeter =2a+b. ( a is representing equal sides)

45=2×16+b

b=45-32=13cm

to calculate area, we use heroins formula

✓s(s-a)(s-a)(s-b)

s= 2(a+b)/2

s=45/2=22.5

✓22.5×6.5×6.5×9.5

✓9030.9375 cm²

Step-by-step explanation:

to find altitude we use

area of triangle=1/2×Base×Altitude

√300.51=1/2×13× A

A=(2√399.51)/13 cm

Answered by mohdanasch21
0

Answer:

perimeter= 45cm

let the third side be x

16+16+x=45

32+x=45

x=13

To find altitude/height, we will use this formula-

√(a^2-b^2)/4

√(16)^2-(16)^2/4

16-16/2

8

height=8

area = 1/2bh

1/2×13×8

13×4=52=area

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