Question

an isosceles triangle has perimeter 50 cm and each of the equal sides is 15 cm . find the area of the triangle ​

Answer 1

Answer:

Area =111.8 sq. cm

Step-by-step explanation:

Given perimeter=50,length of equal sides a=15

Length of other side b=perimeter-a-a

Base b=50-2(15)

=50-30

=20

$height \: h = \sqrt{ {a}^{2} - ( {b \div 2)}^{2} }$

h=√[15²-(20/2)²

h=√225-100

h=√125

h=5√5

$area \: a = (1 \div 2) \times bh$

A=(20×5√5)/2

A=50√5

A=111.8 sq. cm