Question

An isosceles triangle has perimeter
each its equal sides is sim, find its area
(use√15=3.88)​

Answer 1

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ANSWER

Perimeter of isosceles triangle=30cm

Length of equal sides=12cm

Let third side of triangle=xcm

According to problem,

x+12+12=30

x+24=30

x=30−24

x=6

∴ Third side of triangle=6cm

Using Heron's formula

Area of triangle= s(s−a)(s−b)(s−c) sq. units

where s= 2a+b+c

s= 230

=15

Area of triangle=

15(15−12)(15−12)(15−6) cm 2

= 15×3×3×9 cm

=3×3× 15 cm

2=9 15 cm

2

∴ Area of triangle=9

15 cm

2

Hope it helps....

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