AN ISOSCELES TRIANGLE HAS TWO EQUAL SIDE OF LENGTH xcm EACH AND THIRD SIDE OF 9CM. IF ITS PERIMETER IS 24CM WHAT IS THE VALUE OF X
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Step-by-step explanation:
The perimeter of a isosceles triangle:
P = 2 a + b
where:
a = length of the two equal sides
b = third (unequal) side
P = 2 a + b = 24
In this case a = x , b = 9 cm.
2 x + 9 = 24
Subtract 9 to both sides
2 x + 9 - 9 = 24 - 9
2 x = 15
Divide both sides by 2
x = 7.5 cm
Answered by
2
Answer:
Emmanuel Hudson
Apr 18, 2019
The perimeter of a isosceles triangle:
P = 2 a + b
where:
a = length of the two equal sides
b = third (unequal) side
P = 2 a + b = 24
In this case a = x , b = 9 cm.
2 x + 9 = 24
Subtract 9 to both sides
2 x + 9 - 9 = 24 - 9
2 x = 15
Divide both sides by 2
x = 7.5 cm
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