An isosceles triangle has two equal sides of length ‘a’ and angle between them is . The area of the triangle is (A) a2 cos (B) 2a2cos (C) 2a2sin (D) a2 sin
Answers
Answered by
7
area of triangle = 1/2absinC= 1/2bcsinA =1/2ca.sinB
so, angle between two equal sides of isosceles ∆ is [] then ,
area of traingle = 1/2a² sin[]
I think here option is wrong
ar∆ = 1/2a² sin[]
so, angle between two equal sides of isosceles ∆ is [] then ,
area of traingle = 1/2a² sin[]
I think here option is wrong
ar∆ = 1/2a² sin[]
Similar questions