An isosceles triangle have base 12 cm and each of the equal sides equal to 10 cm. Find the length of the altitude of the triangle.
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an isosceles triangle has two equal sides , the length of the base on each side is :
12/2=6
by pythagorean theorem
a square + b square =c square
let height be a
a2 +b2=c2 { 2 is square}
a2=c2-b2
a*a=10*10-6*6
a2=100-36
a2=64
a=root of 64
a=8
base = 12cm and height= 8cm
a =b*h/2
a=12*8 /2
a= 96/2
a=48 cm square
12/2=6
by pythagorean theorem
a square + b square =c square
let height be a
a2 +b2=c2 { 2 is square}
a2=c2-b2
a*a=10*10-6*6
a2=100-36
a2=64
a=root of 64
a=8
base = 12cm and height= 8cm
a =b*h/2
a=12*8 /2
a= 96/2
a=48 cm square
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