Question

an isosceles triangle in which AB= AC where AB= (4x- 3)cm ,AC= (3x + 5 )cm BC = (2x + 3) cm find the perimeter of triangle and value of x

Answer 1

Sine AB=AC

Hence, 4x - 3= 3x +5

= 4x - 3x = 5+3

=x =8

Since perimeter of triangle equal to sum of all sides;

P=AB + AC + BC

=4x - 3+ 3x +5 + 2x +3

=9x + 5

=9*8+5

=72+5

=77cm. It's solved.

Answer 2

ab+ac+bc=180(sum of three angle is 180)
(4x-3)cm+(3x+5)cm+(2x+3)=180
4x+3x+2x-3+5+3=180
9x+5=180
9x=180-5
9x=175
x=175/9
x=19