An Isosceles triangle is inscribed in a circle If that triangle has perimeter 44cm and length of its equal side is 16cm. Find radius of circle
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Answer:
AB=AC12
5
and BC=24cm.
Join OB and OC and OA
Draw AD⊥BC which will pass through
Centre O
OD bisect BC in D
BD=CD=12cm
In right △ABD
AB
2
=AD
2
+BD
2
(12
5
)
2
=AD
2
+BD
2
(12
5
)
2
=AD
2
+(12)
2
144×5=AD
2
+144
720−144=AD
2
AD
2
=576(AD=
576
=24
Let radius of the circle =OA=OB=OC=r
OD=AD−AO=24−r
In right △OBD
r
2
=(12)
2
+(24−r)
2
r
2
=144+576+r
2
−48r
48r = 720
r=720/48=48r
48r=720
r=720/48=15cm.
Radius =15cm.
please do the sum in this way..it is helpful to you
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