Question

An isosceles triangle is to be cut from one edge of a square lamina (as
shown in the figure) such that the remaining portion when suspended
from the apex P of the cut will remain in equilibrium in any position.
The value of h is​

Answer 1

Where is the figure dear???

Leave it come to THE POINT OF ANSWER__

Let M be the mass of square.

Mass per unit area=M÷(l×l).

Mass of isosceles triangle=M÷(l×l)×(1÷2×l×h).

Set origin at apex P.y of com =0

=M×(l÷2-h)-M÷(l×l)×(1÷2×l×h)×(-2÷3×h).

On solving the quadratic equation obtained,

h=(3+or-root 3)÷2

Since h cannot be >l.

Thus h=(3-root 3)÷2.

Answer 2

Answer:

Where's the figure?

h=3-√3÷2

Explanation:

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