Question

an isosceles triangle the equal size exceeds twice the unequal side by 2 CM if the perimeter of the triangle is 34 cm find the length of its sides​

Answer 1

Step-by-step explanation:

perimeter of triangle = 34 cm

let the unequal side be = x

equal sides will be = x + 2

x + 2 + x + 2 + x = 34

3x + 4 = 34

3x = 34 - 4

3x = 30

x = 30/3

x = 10

length of unequal side = x = 10 cm

length of equal side = x + 2 = 10 + 2 = 12 cm

therefore the sides of isosceles triangle are

12 cm, 12 cm, 10cm

hope you get your answer