Math, asked by gopal2510, 27 days ago

an isosceles triangle with 7cm ,5cm and 5cm

Answers

Answered by Techoobant
0

Answer:

Perimeter = 17 cm & Area = 12.49 sq. cm

Step-by-step explanation:

Solution,

Length of base (a) = 7 cm

Length of equal sides (b) = 5 cm

Perimeter of isoceles triangle = ?

Area of isoceles triangles = ?

For perimeter,

Perimeter of isoceles triangle = sum of all sides

= 7 cm + 5 cm + 5 cm

= 17 cm

For area we use the formula of isoceles triangle,

Area of isosceles triangle = (a * root(4 * b^2 - a ^ 2)) / 4

= (7 cm * root(4 * (5 cm)^2 - (7 cm)^2)) / 4

= (7 cm * root( 4 * 25 cm^2 - 49 cm^2)) / 4

= (7 cm * root(100 cm^2 - 49 cm^2)) / 4

= (7 cm * root(51 cm^2)) / 4

= (7 cm * 7.14 cm) / 4

= 49.98 cm^2 / 4

= 12.49 cm^2

This, the required area of isoceles triangle is 12.49 sq. cm

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