Question

An isosceles triangle with base 48cn has area 240 sq cm. Find the remaining two sides of the triangle. Check if answer is 24.51

Answer 1

No its answer is not correct its answer is 26cm
SOLUTION =>
let other equal sides of the triangle be x and base is 48 cm
Now, we will apply heroin's formula,
s(half perimeter) =(a+b+c) /2=(x+x+48)/2
=x+24
Area of triangle =
$240 = \sqrt{s(s - a)(s - b)(s - c) } \\240 = \sqrt{x + 24(x + 24 - x)(x + 24 - x)(x + 24 - 48)}$
240^2=(x+24) (24)(24)(x-24)
240×240/24×24=x^2-24^2
100=x^2-576
100+576=x^2
676=x^2
$x = \sqrt{676}$
x=26cm