An isosceles triangle with equal side 10 cm each and third side 8 cm
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Then your question is find thee area na ?
Sol;
By herons formula √s(s-a)(s-b)(s-c)
S= a+b+c/2 = 10+10+8/2 = 28/2 = 14
So
√14(14-10)(14-10)(14-8) = √14×4×4×6
√7×2×4×4×3×2 = 8√21Cm²
So the area of isoscles triangle is = 8√21cm²Ans
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