Math, asked by kanjumollikasingh, 4 months ago

an isosceles trianglehas perimeter 30 cm and each of the equal sides is 12 cm. find the area of triangle​

Answers

Answered by BlessedMess
77

First,let the third side be x.

It is given that the length of the equal sides us 12 cm and it's perimeter is 30 cm.

So,

30=12+12+x

⇒ 30 = 24 + x

⇒24  + x = 30

⇒  x= 30 - 24

⇒ x = 6

So,the length of the third side is 6 cm.

Thus,the semi perimeter of the isosceles triangle (s) = 30/2 cm =15 cm

By using Heron's Formula,

Area of the triangle,

 =  \sqrt{s(s - a)(s - b)(s - c)}

 =  \sqrt{15(15 - 12)(15 - 12)(15 - 6)}  \:  {cm}^{2}

 =  \sqrt{15 \times 3 \times 3 \times 9}  \:  {cm}^{2}

 = 9 \sqrt{15}  \:  {cm}^{2}

Answered by JankiNath
1

A≈40.25cm²

I have given you the answer in short

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