Question

An isosceles triangular glass prism stands with its base in water as shown. The angles that its two equal sides make with the base are each. An incident ray of light parallel to the water surface internally reflects at the glass-water interface and subsequently re-emerges into the air. Taking the refractive indices of glass and water to be 3/2 and 4/3 respectively. must be at least , value of x is

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Answer 1

Answer:

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Answer 2

Answer:

Refractive index of glass = 3/2

And refractive index of water = 4/3

Rays enter into prism and TIR takes place at glass nd water interface.

According to question,

n2/n1 = 1/sinc = n1/n2

This implies 314/413 = 1/sin c

3 x3/4 x 4 = 1/sin c

This implies cos (90 - C ) = 9/16

So, maximum value of C = sin^-1 (9/16)

C = 34.22 degree

cos = .828 (maximum value)