Question

An isosceles triangular plate of base 4m and altitude 6m is immersed vertically in water. Its axis of symmetry is parallel to and at a depth of 6m from the free water surface. Calculate the magnitude and location of total pressure force.

Answer 1

The force is 793800 N and location is 9m above when an isosceles triangular plate of base 4m and altitude 6m is immersed vertically in water.

Given:

Base length = 4m
Height = 6m
Density = $1000 kg/m^3$
To find:  Magnitude and location
Solution:
Total Pressure is delimited as the material force exercised on an object. The force used is straight to the surface of objects apiece extent. The fundamental recipe for pressure is F/A (Force apiece field). Unit of pressure is Pascals (Pa). Types of Pressures are Absolute, Atmospheric, Differential, and Gauge Pressure.
Center of pressure: The center of pressure is the point place the total total of a pressure field acts on a material, making a force to act through that point. The total force heading acting at the center of pressure is the advantage of the joined vectorial pressure field.

$F= P * A$
$F = pgh * A\\H = 9 m \\F= pgh * AF = 793800$
Therefore the total force is 793800 N

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