Question

An item was sold for Rs540 at a loss of 5%. what was it's cost price​

Answer 1

S.P= ₹ 540, loss%=5%

S.P= ₹ 540, loss%=5%

Let the Cost price = C.P

S.P= ₹ 540, loss%=5%

Let the Cost price = C.PLoss% =( loss/C.P) × 100

S.P= ₹ 540, loss%=5%

Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 100

S.P= ₹ 540, loss%=5%

Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP - 540)/CP ) × 100

S.P= ₹ 540, loss%=5%

Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP - 540)/CP ) × 1005/100 = ( (CP - 540)/CP )

S.P= ₹ 540, loss%=5%

Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP - 540)/CP ) × 1005/100 = ( (CP - 540)/CP ) 1/20 = ( (CP - 540)/CP )

S.P= ₹ 540, loss%=5%

Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP - 540)/CP ) × 1005/100 = ( (CP - 540)/CP ) 1/20 = ( (CP - 540)/CP ) CP = 20 (CP - 540)

S.P= ₹ 540, loss%=5%

Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP - 540)/CP ) × 1005/100 = ( (CP - 540)/CP ) 1/20 = ( (CP - 540)/CP ) CP = 20 (CP - 540)20 = 20CP - 10800

S.P= ₹ 540, loss%=5%

Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP - 540)/CP ) × 1005/100 = ( (CP - 540)/CP ) 1/20 = ( (CP - 540)/CP ) CP = 20 (CP - 540)20 = 20CP - 1080020CP - CP = 10800

S.P= ₹ 540, loss%=5%

Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP - 540)/CP ) × 1005/100 = ( (CP - 540)/CP ) 1/20 = ( (CP - 540)/CP ) CP = 20 (CP - 540)20 = 20CP - 1080020CP - CP = 1080019CP = 10800

S.P= ₹ 540, loss%=5%

Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP - 540)/CP ) × 1005/100 = ( (CP - 540)/CP ) 1/20 = ( (CP - 540)/CP ) CP = 20 (CP - 540)20 = 20CP - 1080020CP - CP = 1080019CP = 10800CP = 10800/19

S.P= ₹ 540, loss%=5%

Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP - 540)/CP ) × 1005/100 = ( (CP - 540)/CP ) 1/20 = ( (CP - 540)/CP ) CP = 20 (CP - 540)20 = 20CP - 1080020CP - CP = 1080019CP = 10800CP = 10800/19CP =₹ 568.42

S.P= ₹ 540, loss%=5%

Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP - 540)/CP ) × 1005/100 = ( (CP - 540)/CP ) 1/20 = ( (CP - 540)/CP ) CP = 20 (CP - 540)20 = 20CP - 1080020CP - CP = 1080019CP = 10800CP = 10800/19CP =₹ 568.42

Hence, the cost price of an item = ₹ 568.42

Answer 2

$\underline\mathfrak\orange{Answer:—}$

We have,

SP = Rs 540

Loss = 5%

CP = ?

.

Therefore,

$SP = CP(1-\dfrac{loss\%}{100})$

put the values in the above equation, we get

$\\\Rightarrow 540 = CP(1-\dfrac{5}{100})\\ \\ \Rightarrow540 = CP\times \dfrac{19}{20}$

$\Rightarrow CP = \dfrac{540 \times 20}{19} = Rs\ 568.42$