An L-shaped object, made of thin rods of uniform mass density, is suspended with a string as shown in figure. If AB = BC, and the angle made by AB with downward vertical is θ, then:
(A) tan θ =
1/(2√3)
(B) tan θ =
1/2
(C) tan θ =
2/(√3)
(D) tan θ =
1/3
[JEE Main 2019]
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1
Answer:
i think it Will be 45 degree
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3
Thus the value of tan θ = 1/3
Option (D) is correct.
Explanation:
Torque = r x F
Wherein
- This can be calculated by using either τ =r1 F or τ =r . F1
- r1 = perpendicular distance from origin to the line of force.
- F1 = component of force perpendicular to line joining force.
mg C1 x1 = mg sinθ
mg C2x2 = (S1S2 - S2C2) mg = mg L / 2 cosθ - mg L sinθ
mg C1x1 = mg C2x2
=> tan θ = 1/3
Thus the value of tan θ = 1/3
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