Question

An LC circuit originally oscillates with frequency f. when the current through the inductor is I=imax/2 find charge on the capacitor.​
Ans is b part

Answer 1

Answer:

As there will be no change in either L or C by changing energy of the oscillations ∴f=( 2π LC1 ) will not change.Thus, the period of oscillation will remain constant.Total energy 2E= 2C( 2Q m ) 2Therefore maximum charge on the capacitor has become 2times of the initial maximum charge Q m Also,21 Li m2'⇒2× 21Li m2⇒i m′= 2imThus, the maximum current that will appear in thecircuit will be 2times of its initial value i mTotal energy is equally divided between capacitor and inductor.Charge on capacitor = 21 [ 2C2Q m2 ]= 2CQ m2 i.e. it is equal to initial maximum charge on the capacitor.

Explanation:

number D