Math, asked by zajeeshz3787, 1 year ago

An n-digit number is a positive number with exactly n digits. Nine hundred distinct n-digit numbers are to be formed using only the three digits 2, 5 and 7. The smallest value of n for which this is possible is

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9

Answers

Answered by Anonymous
26
for such condition 3^n >900
3^6=729
and 3^7=2187
thus least value of n=7
Answered by pinquancaro
27

Answer:

Option 2 - 7

Step-by-step explanation:

Given : An n-digit number is a positive number with exactly n digits. Nine hundred distinct n-digit numbers are to be formed using only the three digits 2, 5 and 7.

To find : The smallest value of n for which this is possible is ?

Solution :

An n-digit number is a positive number with exactly n digits.

For one's spot we have 3 digit,

For second's spot we have 3 digit,

For nth spot we have 3 digit,

The total number of ways to make an n-digit number with only 2,5 and 7 is going to be 3^n

According to question,

3^n\geq 900

\frac{3^n}{3^2}\geq 100

3^{n-2}\geq 100

The value of n in which it is greater than 100.

3^4=81 and 3^5=243

Which means n-2\geq 5

n\geq 7

The smallest value of n for which this is possible is 7.

Therefore, Option 2 is correct.

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