Question

An NCC parade is going at a uniform speed of 6 km/h
through a place under a berry tree on which a bird is
sitting at a height of 12.1 m. At a particular instant the
bird drops a berry. Which cadet (give the distance from
the tree at the instant) will receive the berry on his
uniform ?

Answer 1

Answer:

Explanation:

Let t be the true time of fall 

Initial velcoity=u=0m/s

a=9.8 m/s2

Distance=S=12.1 m

S= ut+1/2 at²

12.1=o+1/2 x 9.8x t²

t²=12.1/4.9=2.46 sec

t=1.57 sec

Cadet velocity=6km/hr=6x5/18=1.66 m/s

Distance = Speed x time

=1.57 x 1.66 =2.6m

The cadet , at 2.6m away from the tree will receive the berry on his uniform.