An npn transistor operates as a common emitter amplifier, with a power gain of 60 dB. The input circuit resistance Is 100 Ω and the output load resistance is 10 kΩ. the common emitter current gain β is:
(A) 6 × 10²
(B) 10²
(C) 60 (D) 10⁴
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An npn transistor operates as a common emitter amplifier, with a power gain of 60 dB. The input circuit resistance Is 100 Ω and the output load resistance is 10 kΩ. the common emitter current gain β is (B) 10²
- Given:
Power gain in dB : Ap = 60 dB
Input ciruit resistance : Ri = 100 Ω
Output load resistance : Rout = 10 KΩ = 10 × 10³ Ω
Current gain : β = ?
- Power gain in dB can be converted using formula:
- Since Power is defined as product of current to the voltage and power gain is defined as the ratio of output power to the input power;
Power gain = Voltage Gain × Current Gain
- Ap = Av × β ...................(1)
Voltage gain (Av) in terms of Current gain can be given as
- ..................(2)
Substituting (2) in (1), we get
Substituting given values, we get
Current Gain = 100 = 10²
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