Chemistry, asked by ag0542222, 4 months ago

An nth-order rate law is often used to model chemical reactions that solely depend on the concentration of a single reactant:

where c = concentration (mole), t = time (min), n = reaction order (dimensionless), and k = reaction rate (min-1 mole1-n). The differential method can be used to evaluate the parameters k and ra. This involves applying a logarithmic transform to the rate law to yield,



Therefore, if the nth-order rate law holds, a plot of the log(-dc/dt) versus log c should yield a straight line with a slope of n and an intercept of log k. Use the differential method and linear regression to determine k and n for the following data for the conversion of ammonium cyanate to urea:

t,min

0

5

15

30

45

c,mole

0.750

0.594

0.420

0.291

0.223

Step-by-step solution:

Step 1 of 5

Following is the given table:

t, min

c, mole

0

0.75

5

0.594

15

0.420

30

0.291

45

0.223

Following is given equation for pressure gradient for laminar flow

Applying logarithmic transformation to the rate law we get
An nth-order rate law is often used to model chemical reactions that solely depend on the concentration of a single reactant:

where c = concentration (mole), t = time (min), n = reaction order (dimensionless), and k = reaction rate (min-1 mole1-n). The differential method can be used to evaluate the parameters k and ra. This involves applying a logarithmic transform to the rate law to yield,



Therefore, if the nth-order rate law holds, a plot of the log(-dc/dt) versus log c should yield a straight line with a slope of n and an intercept of log k. Use the differential method and linear regression to determine k and n for the following data for the conversion of ammonium cyanate to urea:

t,min

0

5

15

30

45

c,mole

0.750

0.594

0.420

0.291

0.223

Step-by-step solution:

Step 1 of 5

Following is the given table:

t, min

c, mole

0

0.75

5

0.594

15

0.420

30

0.291

45

0.223

Following is given equation for pressure gradient for laminar flow

Applying logarithmic transformation to the rate law we get


Please solve it.



Answers

Answered by divyajtawar
0

Answer:

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