An o bject is placed at a distance of 30 cm from a concave lens of focal length 15 cm. find distance off image from lens.
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Solution : Here, `u = -30 cm, f = -15 cm, v = ?` <br> As `(1)/(v) - 1/u = (1)/(f)`, <br> `(1)/(v) + 1/30 = 1/(-15) or (1)/(v) = - 1/15 - 1/30 = (-2 - 1)/30 = (-3)/30 or v = -30/3 = -10.0 cm` <br> As v is negative, the image must be virtual and erect.
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