Question

An o object of 5 kg is moving in a straight line with a uniform speed of 10 metre per second the resultant force on the object is
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Answer 1

$\huge \bigstar \pink {\underbrace \mathfrak{Answer :}} \bigstar$

${\fbox \red{Force = 0 \: newton}}$

Given :-

• Mass of object (m) = 5kg
• Initial velocity (u) = 10m/s
• Final velocity (v) = 10 m/s

To Find:-

• The resultant Force (F)

Solution:-

As we know that the formula for acceleration is given by,

$> Acceleration = \frac{v -u }{t}$

$> Acceleration = \frac{10 - 10}{t}$

$> Acceleration = \frac{0}{t}$

$> Acceleration = 0ms - 2$

Now, on applying the formula of force we get,

→ Force = mass×Acceleration

→ Force = 5kg × 0 ms -²

→ Force = 0kg. ms -²

${\fbox \blue{Force = 0 \: newton}}$

Answer 2

Given : An  object of 5 kg is moving in a straight line with a uniform speed of 10 metre per second

To Find : the resultant force on the object

Solution:

mass = 5 kg

moving in a straight line with a uniform speed of 10 metre per second

Hence constant velocity of 10 m/s

acceleration   a= dv/dt

v = Velocity is constant

Hence a = 0

acceleration is rate of change of velocity,  as velocity is constant of rate of change of velocity is zero

so acceleration is zero

a = 0

m = 5 kg

F = ma

F = Force

F = 5 * 0  = 0

resultant force on the object is 0 N

or No force

Note : Air resistance / friction  is assumed zero here

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