Question

An objdct of 1 kg is dropped from the top of a 125 m high towet. Its kinetic energg while striking the ground shall be

Answer 1

Answer:

M = 1kg

H = 125m

K.e = ?

K. E = 1/2 * m * v^2

First we need to find the velocity to calculate kinetic energy of an object.

Apply. v^2 = u^2 + 2gh

u = 0

g = 9.8

h = 125

v^2 = 0^2 + 2*9.8*125

v^2 = 2450

v = 49.49 m/s

Now find K. E

1/2 * 1 * 49.49 * 49.49

= 1224.63 kg.m^2/s^2

Thanks