Question

An obje a of mass
m and velocity v has kinetic energyof 200 J
Find the new kinetic
energy if the
mass of the
object becomes
double
& velocity still remains
the same?​

Answer 1

Answer:

the kinetic energy become double

Answer 2

${\large{\pmb{\sf{\bigstar \:{\underline{Correct \: QuEstion...}}}}}}$

⋆ An object of mass,m and velocity,v has kinetic energy as 200 J. Find the new kinetic energy if the mass of the object becomes double and velocity still remains the same.

${\large{\pmb{\sf{\bigstar \:{\underline{GivEn \: That...}}}}}}$

⋆ An object of mass m and velocity v has kinetic energy as 200 Joules.

★ Situations regards this question are mentioned below:

⋆ The mass of the object becomes double.

⋆ Velocity still remains the same.

${\large{\pmb{\sf{\bigstar \:{\underline{To \: FiNd...}}}}}}$

⋆ The new kinetic energy is the mass of the object becomes double.

⋆ The new kinetic energy is the velocity still remains the same.

${\large{\pmb{\sf{\bigstar \:{\underline{SoluTion...}}}}}}$

⋆ The new kinetic energy is the mass of the object becomes double = 400 Joules

⋆ The new kinetic energy is the velocity still remains the same = 400 Joules

${\large{\pmb{\sf{\bigstar \:{\underline{Using \: ConcEpt...}}}}}}$

⋆ Formula to find out the kinetic energy =

${\small{\underline{\boxed{\sf{K.E \: = \dfrac{1}{2} mv^{2}}}}}}$

${\large{\pmb{\sf{\bigstar \:{\underline{Full \; SoluTion...}}}}}}$

${\underline{\sf{According \: to \: Situation \: 1)}}}$

${\small{\underline{\boxed{\sf{K.E \: = \dfrac{1}{2} mv^{2}}}}}} \\ \\ :\implies \sf K.E \: = \dfrac{1}{2} mv^{2} \\ \\ :\implies \sf 200 \: = \dfrac{1}{2} mv^{2} \\ \\ :\implies \sf 200 \times 2 = 1 \: mv^{2} \\ \\ :\implies \sf 400= 1 \: mv^{2} \\ \\ :\implies \sf 400= mv^{2} \\ \\ :\implies \sf mv^{2} = 400$

Henceforth, we get mv² as 400

${\underline{\sf{According \: to \: Situation \: 2)}}}$

~ Now as it's given that the mass of the object becomes double(2) and velocity still remains the same.

${\small{\underline{\boxed{\sf{K.E \: = \dfrac{1}{2} mv^{2}}}}}} \\ \\ :\implies \sf K.E \: = \dfrac{1}{2} mv^{2} \\ \\ :\implies \sf K.E \: = \dfrac{1}{2} \: 2mv^{2} \\ \\ :\implies \sf K.E \: = \dfrac{1}{\cancel{2}} \: \cancel{2}mv^{2} \\ \\ :\implies \sf K.E \: = 1 \: mv^{2} \\ \\ :\implies \sf K.E \: = mv^{2} \\ \\ :\implies \sf K.E \: = 400 \: Joules$

Henceforth, the new kinetic energy is the mass of the object becomes double and the new kinetic energy is the velocity still remains the same is 400 Joules