An object 1-5 cm high when placed in front of a concave mirror, produces a virtual image 3 cm high. If the object is placed at a distance of 6 cm from the pole of the mirror, calculate : (6) the position of the image: (ii) the focal length of the mirror
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it's a concave mirror.
h=+2 cm, H=+3 cm ,u=-8 cm
H/h=v/u
3/2=v/-8
-24/2=v
-12 cm = v
now,
1/v+1u=1/f
-1/12-1/8
-8-12/96
-20/96
-10/48
f=-4.8 cm
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