Question

an object 1 centimetre high is placed on the axis and 15 cm from a concave mirror of focal length 10 cm find the position and nature and magnification and size of the image answer the qestion by explaining step by step​

Answer 1

Explanation:

u=15cm

f=10cm

v=?

so

1/f=1/v+1/u

1/10=1/v+1/15

1/10— 1/15=1/v

3-2\30= 1/v

1/30 = 1/v

30 =v

so the image will be larged in size real & inverted & image is formed beyond c

&

magnification (m)= –v/u

= –30/15

=–2

so m=h'/h

–2= h'/1

h'=–2

Answer 2

Heya!!

Plz refer to the attachment for the answer...