Question

An object 1 centimetre high is placed on the axis and 15 cm from a concave mirror of focal length 10 cm find the position and nature and magnification and size of the image answer the question by explaining step by step​.... NO SPAM ANSWERS PLEASE...

Answer 1

Answer:

hope it helps..

:)

Explanation:

Given:

object height=1cm

u=-15cm

f=-10cm

$\frac{1}{v} {+}\frac{1}{u} {=}\frac{1}{f}$

$\frac{1}{v} {=}\frac{1}{f} {-}\frac{1}{u}$        

$\frac{1}{v} {=}{-}\frac{1}{10} {-}\frac{1}{-15}$

$\frac{1}{v}{=}{-}\frac{1}{10} {+}\frac{1}{15}$

$\frac{1}{v} {=}\frac{-1}{30}$

v=-30cm

size=-v/u

      = -(-30/-15)

      =-2

Answer 2

Heya!!

Plz refer to the attachment for the answer...