Question

An object 1 cm height is placed on the axis
15 cm from a concave mirror of focal
length 10cm Find the position, nature megnificatio size of the image​

Answer 1

Answer:

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Explanation:

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Answer 2

GiveN :

• Object Height (Ho) = 1 cm
• Object Position (u) = - 15 cm
• Focal length (f) = - 10 cm
• Concave Mirror

To FinD :

• Position, size, nature of the image

SolutioN :

Use mirror formula :

⇒ 1/f = 1/v + 1/u

⇒ 1/v = 1/f - 1/u

⇒1/v = 1/-10 - (1/-15)

⇒ 1/v = -1/10 + 1/15

⇒ 1/v = (-3 + 2)/30

⇒ 1/v = -1/30

⇒v = - 30 cm

$\therefore$ Image is placed at distance of -30 cm from mirror.

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Now, use formula for magnification :

➠ m = -v/u = H'/Ho

⇒-(-30)/-15 = H'/1

⇒30/-15 = H'

⇒H' = -2 cm

$\therefore$ Image height is - 2cm

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• Nature of Image is Real and Inverted.
• Size of image is Enlarged.