Question

an object 1 cm high is held near concave mirror of magnification +,- 10 .how tall will be Image. also describe the nature of image ​

Answer 1

Explanation:

h'/h = m

given object height 1cm

when it forms a real image than magnification will be (-)

so ,

h'/h = -10

h'/1cm = -10

h' = -10cm ( inverted real image enlarged )

when +10 then i will be virtual erect enlarged image