Physics, asked by bhumirastogi05, 8 months ago

an object 1 cm high is placed at a distance of 25 cm from a concave mirror of focal length 15 cm. Find the position, nature and height of the image. complete explanation

Answers

Answered by Anonymous
3

Answer:

size of object , H₀ = 1 cm

object distance , u = -25 cm

focal length of concave mirror , f = -15 cm

Use formula ,

1/v + 1/u = 1/f

⇒1/v + 1/-25 = 1/-15

⇒1/v = 1/-15 + 1/25 = (-25 + 15)/375 = 1/-37.5 cm

⇒ v = - 37.5 cm ,

∴ image is formed object side , 37.5 cm from pole

of concave mirror.

Now, use formula,

Hi/H₀ = -u/v

Where Hi is the size of image .

Now, Hi/1cm = -(-37.5cm)/(-25cm)

Hi = -1 × 37.5/25 cm = -3/2 cm= -0.67 cm

# size of image = -0.67 cm

the image is formed behind the mirror. Since the

Distance is Negative, thus the Image is Real.

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