Question

An object 1 cm high produces a real image 1.5 cm high when placed at a distance of 15 cm from a concave mirror. Calculate the position of the image and the magnification.
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Answer 1

Answer:

the image will be formed at a distance of -22.5cm from pole and the magnification will be -1.5 times of the object

Answer 2

Answer:

Given:

object height, h = 1 cm

image height, h' = 1.5 cm

object distance, u = -15 cm (-ve sign because object taken behind the mirror

To find:

Position of image, v

Magnification, m

Solution:

m = h'/h = -v/u

-v = h'u / h

= 1.5 × -15 / 1

-v = -22.5

v = 22.5 cm

As the image is positive, it is virtual and erect.

Therefore, image is formed at a distance of 22.5 cm behind the mirror.

Magnification, m = h' / h

m= 1.5 / 1

= 1.5

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