Question

an object 1 cm high produces a real image 1.5 CM when placed at a distance of 15 cm from a concave mirror calculate the position of the image and the magnification

Answer 1

Object high H1 = 1cm

Image height  H2 = 1.5cm

Object distance u = -15cm (object is taken behind the mirror)

Since, magnification = image height/object height,

M = H2/H1 = 1.5/1 = 1.5

Since, also, magnification = image distance/ object distance

=> 1.5 = image distance/-15

=> image distance = -22.5cm

=>22.5 cm behind the mirror

Answer 2

hope this helps u

h'=1.5cm

h=1cm

u = -15cm

h'/h= -v/u

-v = h'*u/h

- v = (1.5) (-15) / 1

- v = - 22.5

v = 22.5

The image is positive, therefore it is a virtual and erect image.

magnification = h'/h

                       = 1.5/1

magnification = 1.5

by hariprasath @ rukumanikumaran