Question

an object 10 cm from pole of concave mirror forms real and inverted image at 15cm. what is the radius of curvature?

Answer 1

⇒Radius of curvature is 15cm

⇒So focal length will be 7.5 cm

⇒So the object is placed between centre of curvature and focus so image will be REAL,MAGNIFIED and of course INVERTED.

Answer 2

Answer:

Radius of Curvature is –12 cm

Explanation:

given, u = – 10 cm

v = – 15 cm

using mirror formula

1 / f = 1 / v + 1 / u

1 / f = 1 / –15 + 1 / –10

1 / f = – ( 2 + 3 ) / 30

1 / f = – ( 5 ) / 30

1 / f = – 1 / 6

f = – 6 cm

R = 2 f

= – 12 cm