An object 10 cm high is placed at a distance of 15 cm from a convex lens of focal length 12 cm. Determine the position, nature magnification and height of the image
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Answer:
1/f=1/v-1/u
1/u=1/v-1/f
=(-1/15)-(-1/12)
=(-4/60)-(-5/60)
= 1/60
u=60cm
m=v/u
=15/60
=1/4
=0.25
0.25=h'/h
=h'/10
h'=.25*10
= 2.5 cm
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