An object 10cm in height is placed at a distance of 36cm from a concave mirror. The image
is formed 18cm in front of the mirror. Find the height of the image.
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Step-by-step explanation:
sumof−48and−58is=−106
=102−(−106)
=102+106
=208Substract the sum of -42 and -147 from the difference of -283 and -413
Answered by
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Given :
- We have been given an object with a height of 10 cm
- When it is placed in front of a Concave Mirror , at a Distance of 36 cm from it
- Image is formed at 18 cm
To Find :
- We have to find the height of Image
Concept Used :
Magnification is the ratio of Height of Image produced to the Height of object
Mathematically , it can be written as
Where the variables stand for
- = Height of Image
- = Height of Object
There is one more way to write the formula in terms of Object and Image Distance
Solution :
Using proper sign convention in the given Question , we have been given that
- Object Distance (u) = - 36 cm
- Image Distance (v) = - 18 cm
- Height of Object = 10 cm
Equating both formulas of Magnification
Putting the values of all the given variables in the above Equation
Hence Height of Image is 5 cm, minus sign here indicates that the image is real and inverted
Properties of Image :
- Image formed is real and inverted
- Image is formed Diminished
- A Concave Mirror is also known as Converging Mirror
- It converges all the right rays falling on its surface at a point know as focus
- Imagine formed can be real or virtual
- Image formed me enlarge or Diminished
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