An object 10cm in length is placed at a distance of 30 cm infront of a convex mirror of radius of curvature 50cm find the position of the image it's nature and size
Answers
Answer:
Explanation:
The properties of the image is virtual,diminished,errect
1/u+1/v=1/f
-1/10+1/v=1/15
1/v=3+2/30
1/v=1/6
v=6
According to the linear magnification
Height of the image/Height of the object
-6/10
.6
Again
.6=Height of the image/5
Height of the image is 3.0cm that is 3cm
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Vinni Thomas, M Sc, MPhil, M S Physics & Applied Physics, Madurai Kamaraj University, Tamil Nadu, India (1992)
Answered January 23, 2018
virtual image, formed 6 cm behind the mirror and the size is 1.8 cm
2.3K views
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Answer:
image formed is virtual,erect and diminished
Explanation:
Given:-
object height,h=10cm
object distance,u=-30cm
radius of curvature,R=50cm
focal length,f=R/2=50/2=25cm
mirror formula:-
1/f=1/v+1/u
1/25=-1/30+1/v
1/v=1/25+1/30
1/v=6+5/150
1/v=11/150
v=150/11
v=13.6cm
Therefore image is formed at a distance of 13.6cm behind the convex mirror. Thus it is Virtual and Erect.
m=-v/u
m=-13.6/-30
m=0.45
Again,
m=h`/h
0.45= h`/10
h`= 4cm
Therefore image formed is diminished