An object 15 cm in length is placed at a distance of 10 cm in front of a convex mirror of focal length 15 cm. Find the position ,nature and size of the image formed.
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1/f= 1/u + 1/v.
1/15=1/-10 +1/v.
1/v = 1/15+1/10.
1/v = 2+3/30.
1/v = 5/30 = 1/6.
so v = 6 cm.
The object is diminished , it is virtual and erect .
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