Question

An object 18 meters in the first. 3 sec, 02 meters in the next. 3 soc and 14 meters in the last 3 sec. If so overage move.​

Answer 1

Answers:-

Distances travelled

• 18m,2m,14m

Time taken

• 3s,3s,3s

We know

$\boxed{\sf Average\:Speed=\dfrac{Total\:Distance}{Total\:Time}}$

$\\ \sf\longmapsto Average\:Speed=\dfrac{18+2+14}{3+3+3}$

$\\ \sf\longmapsto Average\:speed=\dfrac{34}{9}$

$\\ \sf\longmapsto Average\:Speed=3.8m/s$