an object 1cm high produces a real image 1.5 cm high when placed at a distance of 15 cm from a concave mirror. calculate the position and magnification
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Answered by
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as it is a concave lens the image will always be formed on the same side of the lens where the object is placed
U can also calculate the position by the formula... Length of image /length of object = distance of the image /distance of the object
1.5/1=15/x =>x=10 cm... Which means that the image is on the same side where the object is placed....
Magnification =length of the image
________________
Length of the object
=>1.5/1 = 1.5
Hope it helps!
U can also calculate the position by the formula... Length of image /length of object = distance of the image /distance of the object
1.5/1=15/x =>x=10 cm... Which means that the image is on the same side where the object is placed....
Magnification =length of the image
________________
Length of the object
=>1.5/1 = 1.5
Hope it helps!
Answered by
0
magnification -3/2
position of image = -{1.5 ×3/2 }
position of image = -{1.5 ×3/2 }
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