Question

An object 1cm high produces a real image 2cm high when placed at distance of 15cm from convex lens.Calculate the position of the image and the magnification and also find the focal length of the lens.

Answer 1

Answer:

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Answer 2

Image distance is 30 cm and magnification is -2

Given

Object distance = 1cm

Image distance  = 2 cm

Object height = 15 cm

To Find

We need to find the position of the image and the magnification.

Solution

The real image that is produced by convex lens is inverted.

magnification m = - $\frac{v}{u}$

                            = $\frac{image distance}{object distance}$  =  $\frac{image object}{object height}$

                             = - $\frac{2}{1}$ = - $\frac{x}{15}$

Hence m = -2       v = image distance = +30cm

From the lens formula

$\frac{1}{f}$  = $\frac{1}{v}- \frac{1}{u}$

$\frac{1}{f}$  = $\frac{1}{30} - \frac{1}{-15}$

f = 10 cm

Hence image distance is 30 cm and magnification is -2

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